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# Practice Simplifying Algebraic Expressions - Video & Lesson Transcript

In this lesson, we'll practice simplifying a variety of algebraic expressions. We'll use two key concepts, combining like terms and the distributive property, to help us simplify.

If you've ever played a sport, you know the importance of practice. No track star just shows up at a meet and expects to run a record-breaking 100 meters without training. The more challenging the concept, the more practice you need. If you ever watch professional football, you know that even with an incredible amount of practice, athletes can still make mistakes sometimes; a receiver may forget a route or a punt returner may drop the ball.

But we know we can get better at whatever we're trying to accomplish with practice. What's true in sports is also true in algebra. Simplifying algebraic expressions can be as tricky as mastering a play in football. Fortunately, when we practice algebra, we're unlikely to get knocked to the ground - unless you're playing full-contact algebra. But let's not do that here.

## Simplifying Algebraic Expressions

Here we're going to practice simplifying algebraic expressions. **Simplifying algebraic expressions** is more or less defined by its title. It involves distributing terms across parentheses and combining like terms in order to make an expression simpler. By simpler, we usually mean shorter, or more condensed.

Why is this useful? Algebraic expressions can get cumbersome with all their various bits and pieces. Think of it like food. What if every time you wanted a cookie, you had to ask for it by its parts - flour, sugar, butter, eggs, etc. - as opposed to just saying 'I want a cookie'? That would be tedious, and it would interfere with your cookie eating. When we simplify an expression, we're combining what we can so we're just dealing with cookies, not the things that make up cookies.

There are two main skills involved in simplifying algebraic expressions. First, there's **combining like terms**. This is the process of simplifying expressions by joining terms that have the same variable. So if you have *x* + 2*x*, you can combine them to get 3*x*. If you have 5*x*^2 + 3*x*^2 + 9*x*, you can only combine the 5*x*^2 and 3*x*^2 since they are the only terms that share the same exponent. But we can still make that expression simpler by saying 8*x*^2 + 9*x*.

Second, there's the **distributive property**. This helpful law tells us that *a*(*b* + *c*) = (*ab*) + (*ac*). So, let's say we have 7(*x* + 2*y*). Since they're not like terms, we can't add that *x* and 2*y*. But the distributive property tells us we can distribute

the 7 across the parentheses, giving us 7*x* + 14*y*.

## Practice Problems

Okay, time for some practice. Let's start simple: 2*y* + 4*y* + 9. How can we simplify this? Well, we have two like terms: 2*y* and 4*y*. Both of these terms have the same exponent, *y*. Let's combine them to get 6*y* + 9. Can we go any further? No. The 6*y* and 9 don't share an exponent, so that's as far as we can simplify this one.

Here's a good one: 9 + 3*t* - 5. In this one, all we can combine are the 9 and the -5. So our final expression is 4 + 3*t*. That's it.

Those first two were a good warm-up. Let's try a longer one. What if we have 3*x*^2 + 4*x* + *x*^2 + 2 + 11*x*? A good first step is to get like terms next to each other. What are our like terms? 4*x* and 11*x* both have an *x*. What about 3*x*^2 and *x*^2? They are like terms as well. If we move things around, we get 3*x*^2 + *x*^2 + 4*x* + 11*x* + 2. Now we just need to combine the like terms. We add 3*x*^2 and *x*^2 to get 4*x*^2. Then we combine 4*x* and 11*x* to get 15*x*. So our simplified expression is 4*x*^2 + 15*x* + 2. That's much better!

Up to this point, we've only dealt with one variable. That's kind of like flag football. Let's jump to the NFL by using two: 9*m* + 8*n* + 3*mn* + 4*m* -2*mn* + *n*. It's a little trickier with multiple variables, isn't it? But let's do the same thing we did before - moving like terms next to each other. There are two terms with just one *m*: 9*m* and 4*m*. Then there are two with one *n*: 8*n* and *n*. What else? Those two with an *mn*? They're like terms, too. So with a little shuffling, we have 9*m* + 4*m* + 8*n* + *n* + 3*mn* - 2*mn*. 9*m* + 4*m* is 13*m*. 8*n* + *n* is 9*n*. And 3*mn* - 2*mn* is just *mn*. That gives us 13*m* + 9*n* + *mn*.

Let's do one with some serious exponent work: (5*x*^2*y*)^3. First, let's handle that 5 cubed. That's 125. And what do you do with an exponent raised to an exponent? You multiply them together. So that *x*^2 to the third will be *x*^6. And the *y* will just become *y*^3. So our simplified expression is 125(*x*^6)(*y*^3).

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Category: Homework